filter documentation updated

docs/filters.md

@@ -35,15 +35,15 @@ ldapjs object(s).  If the filter is "complex", it will be a "tree" of objects.
 For example:
 
 ```js
-const parseFilter = require('ldapjs').parseFilter;
+const parseFilter = require("ldapjs").parseFilter;
 
-const f = parseFilter('(objectclass=*)');
+const f = parseFilter("(objectclass=*)");
 ```
 
 Is a "simple" filter, and would just return a `PresenceFilter` object. However,
 
 ```js
-const f = parseFilter('(&(employeeType=manager)(l=Seattle))');
+const f = parseFilter("(&(employeeType=manager)(l=Seattle))");
 ```
 
 Would return an `AndFilter`, which would have a `filters` array of two
@@ -112,9 +112,9 @@ map to:
 
 ```js
 {
-  initial: 'foo',
-  any: ['bar', 'cat'],
-  final: 'dog'
+  subInitial: 'foo',
+  subAny: ['bar', 'cat'],
+  subFinal: 'dog'
 }
 ```
 
@@ -124,9 +124,9 @@ key matching `attribute` and the "regex" matches the value
 ```js
 const f = new SubstringFilter({
   attribute: 'cn',
-  initial: 'foo',
-  any: ['bar'],
-  final: 'baz'
+  subInitial: 'foo',
+  subAny: ['bar'],
+  subFinal: 'baz'
 });
 
 f.matches({cn: 'foobigbardogbaz'});  => true
@@ -242,7 +242,7 @@ equality filters):
 (|(cn=foo)(sn=bar))
 ```
 
-The `matches()` method will return true IFF the passed in object matches *any*
+The `matches()` method will return true IFF the passed in object matches _any_
 of the filters in the `filters` array.
 
 ```js